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3(x+3)8x=21
We move all terms to the left:
3(x+3)8x-(21)=0
We multiply parentheses
24x^2+72x-21=0
a = 24; b = 72; c = -21;
Δ = b2-4ac
Δ = 722-4·24·(-21)
Δ = 7200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7200}=\sqrt{3600*2}=\sqrt{3600}*\sqrt{2}=60\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-60\sqrt{2}}{2*24}=\frac{-72-60\sqrt{2}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+60\sqrt{2}}{2*24}=\frac{-72+60\sqrt{2}}{48} $
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