3(x+3)=(x+3)+(x)+(2x-3)

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Solution for 3(x+3)=(x+3)+(x)+(2x-3) equation: 



3(x+3)=(x+3)+(x)+(2x-3)

We move all terms to the left:

3(x+3)-((x+3)+(x)+(2x-3))=0

We multiply parentheses

3x-((x+3)+x+(2x-3))+9=0



We calculate terms in parentheses: -((x+3)+x+(2x-3)), so:

(x+3)+x+(2x-3)

We add all the numbers together, and all the variables

x+(x+3)+(2x-3)

We get rid of parentheses

x+x+2x+3-3

We add all the numbers together, and all the variables

4x

Back to the equation:

-(4x)



We add all the numbers together, and all the variables

-1x+9=0

We move all terms containing x to the left, all other terms to the right

-x=-9

x=-9/-1

x=+9

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