3(x+3)=2(3x+18)

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Solution for 3(x+3)=2(3x+18) equation: 



3(x+3)=2(3x+18)

We move all terms to the left:

3(x+3)-(2(3x+18))=0

We multiply parentheses

3x-(2(3x+18))+9=0



We calculate terms in parentheses: -(2(3x+18)), so:

2(3x+18)

We multiply parentheses

6x+36

Back to the equation:

-(6x+36)



We get rid of parentheses

3x-6x-36+9=0

We add all the numbers together, and all the variables

-3x-27=0

We move all terms containing x to the left, all other terms to the right

-3x=27

x=27/-3

x=-9

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