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3(x+3)=2(5-x)
We move all terms to the left:
3(x+3)-(2(5-x))=0
We add all the numbers together, and all the variables
3(x+3)-(2(-1x+5))=0
We multiply parentheses
3x-(2(-1x+5))+9=0
We calculate terms in parentheses: -(2(-1x+5)), so:We get rid of parentheses
2(-1x+5)
We multiply parentheses
-2x+10
Back to the equation:
-(-2x+10)
3x+2x-10+9=0
We add all the numbers together, and all the variables
5x-1=0
We move all terms containing x to the left, all other terms to the right
5x=1
x=1/5
x=1/5
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