3(x+3)=3(2x-1)+6

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Solution for 3(x+3)=3(2x-1)+6 equation: 



3(x+3)=3(2x-1)+6

We move all terms to the left:

3(x+3)-(3(2x-1)+6)=0

We multiply parentheses

3x-(3(2x-1)+6)+9=0



We calculate terms in parentheses: -(3(2x-1)+6), so:

3(2x-1)+6

We multiply parentheses

6x-3+6

We add all the numbers together, and all the variables

6x+3

Back to the equation:

-(6x+3)



We get rid of parentheses

3x-6x-3+9=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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