3(x+3)=36-2(x+6)

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Solution for 3(x+3)=36-2(x+6) equation: 



3(x+3)=36-2(x+6)

We move all terms to the left:

3(x+3)-(36-2(x+6))=0

We multiply parentheses

3x-(36-2(x+6))+9=0



We calculate terms in parentheses: -(36-2(x+6)), so:

36-2(x+6)

determiningTheFunctionDomain
-2(x+6)+36

We multiply parentheses

-2x-12+36

We add all the numbers together, and all the variables

-2x+24

Back to the equation:

-(-2x+24)



We get rid of parentheses

3x+2x-24+9=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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