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3(x+3)=4(x-3)
We move all terms to the left:
3(x+3)-(4(x-3))=0
We multiply parentheses
3x-(4(x-3))+9=0
We calculate terms in parentheses: -(4(x-3)), so:We get rid of parentheses
4(x-3)
We multiply parentheses
4x-12
Back to the equation:
-(4x-12)
3x-4x+12+9=0
We add all the numbers together, and all the variables
-1x+21=0
We move all terms containing x to the left, all other terms to the right
-x=-21
x=-21/-1
x=+21
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