3(x+3)=4x+(-2)+(-2x)

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Solution for 3(x+3)=4x+(-2)+(-2x) equation: 



3(x+3)=4x+(-2)+(-2x)

We move all terms to the left:

3(x+3)-(4x+(-2)+(-2x))=0

We multiply parentheses

3x-(4x+(-2)+(-2x))+9=0



We calculate terms in parentheses: -(4x+(-2)+(-2x)), so:

4x+(-2)+(-2x)

determiningTheFunctionDomain
4x+(-2x)+(-2)

We add all the numbers together, and all the variables

4x+(-2x)-2

We get rid of parentheses

4x-2x-2

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We get rid of parentheses

3x-2x+2+9=0

We add all the numbers together, and all the variables

x+11=0

We move all terms containing x to the left, all other terms to the right

x=-11

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