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3(x+3)=6(x+1)
We move all terms to the left:
3(x+3)-(6(x+1))=0
We multiply parentheses
3x-(6(x+1))+9=0
We calculate terms in parentheses: -(6(x+1)), so:We get rid of parentheses
6(x+1)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
3x-6x-6+9=0
We add all the numbers together, and all the variables
-3x+3=0
We move all terms containing x to the left, all other terms to the right
-3x=-3
x=-3/-3
x=1
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