3(x+3)=8(x-2)-5

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Solution for 3(x+3)=8(x-2)-5 equation: 



3(x+3)=8(x-2)-5

We move all terms to the left:

3(x+3)-(8(x-2)-5)=0

We multiply parentheses

3x-(8(x-2)-5)+9=0



We calculate terms in parentheses: -(8(x-2)-5), so:

8(x-2)-5

We multiply parentheses

8x-16-5

We add all the numbers together, and all the variables

8x-21

Back to the equation:

-(8x-21)



We get rid of parentheses

3x-8x+21+9=0

We add all the numbers together, and all the variables

-5x+30=0

We move all terms containing x to the left, all other terms to the right

-5x=-30

x=-30/-5

x=+6

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