3(x+4)+11=2(x+3)

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Solution for 3(x+4)+11=2(x+3) equation: 



3(x+4)+11=2(x+3)

We move all terms to the left:

3(x+4)+11-(2(x+3))=0

We multiply parentheses

3x-(2(x+3))+12+11=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

3x-(2x+6)+23=0

We get rid of parentheses

3x-2x-6+23=0

We add all the numbers together, and all the variables

x+17=0

We move all terms containing x to the left, all other terms to the right

x=-17

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