3(x+4)+11=8x-5(-3)

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Solution for 3(x+4)+11=8x-5(-3) equation: 



3(x+4)+11=8x-5(-3)

We move all terms to the left:

3(x+4)+11-(8x-5(-3))=0

We multiply parentheses

3x-(8x-5(-3))+12+11=0



We calculate terms in parentheses: -(8x-5(-3)), so:

8x-5(-3)

We add all the numbers together, and all the variables

8x+15

Back to the equation:

-(8x+15)



We add all the numbers together, and all the variables

3x-(8x+15)+23=0

We get rid of parentheses

3x-8x-15+23=0

We add all the numbers together, and all the variables

-5x+8=0

We move all terms containing x to the left, all other terms to the right

-5x=-8

x=-8/-5

x=1+3/5

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