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3(x+4)+11=8x-5(x-3)
We move all terms to the left:
3(x+4)+11-(8x-5(x-3))=0
We multiply parentheses
3x-(8x-5(x-3))+12+11=0
We calculate terms in parentheses: -(8x-5(x-3)), so:We add all the numbers together, and all the variables
8x-5(x-3)
We multiply parentheses
8x-5x+15
We add all the numbers together, and all the variables
3x+15
Back to the equation:
-(3x+15)
3x-(3x+15)+23=0
We get rid of parentheses
3x-3x-15+23=0
We add all the numbers together, and all the variables
8!=0
There is no solution for this equation
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