3(x+4)+1=6x-3(-4+x)

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Solution for 3(x+4)+1=6x-3(-4+x) equation: 



3(x+4)+1=6x-3(-4+x)

We move all terms to the left:

3(x+4)+1-(6x-3(-4+x))=0

We add all the numbers together, and all the variables

3(x+4)-(6x-3(x-4))+1=0

We multiply parentheses

3x-(6x-3(x-4))+12+1=0



We calculate terms in parentheses: -(6x-3(x-4)), so:

6x-3(x-4)

We multiply parentheses

6x-3x+12

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

3x-(3x+12)+13=0

We get rid of parentheses

3x-3x-12+13=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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