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3(x+4)+2=2(x-6)-3x
We move all terms to the left:
3(x+4)+2-(2(x-6)-3x)=0
We multiply parentheses
3x-(2(x-6)-3x)+12+2=0
We calculate terms in parentheses: -(2(x-6)-3x), so:We add all the numbers together, and all the variables
2(x-6)-3x
We add all the numbers together, and all the variables
-3x+2(x-6)
We multiply parentheses
-3x+2x-12
We add all the numbers together, and all the variables
-1x-12
Back to the equation:
-(-1x-12)
3x-(-1x-12)+14=0
We get rid of parentheses
3x+1x+12+14=0
We add all the numbers together, and all the variables
4x+26=0
We move all terms containing x to the left, all other terms to the right
4x=-26
x=-26/4
x=-6+1/2
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