3(x+4)+2=8-(6-x)

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Solution for 3(x+4)+2=8-(6-x) equation: 



3(x+4)+2=8-(6-x)

We move all terms to the left:

3(x+4)+2-(8-(6-x))=0

We add all the numbers together, and all the variables

3(x+4)-(8-(-1x+6))+2=0

We multiply parentheses

3x-(8-(-1x+6))+12+2=0



We calculate terms in parentheses: -(8-(-1x+6)), so:

8-(-1x+6)

determiningTheFunctionDomain
-(-1x+6)+8

We get rid of parentheses

1x-6+8

We add all the numbers together, and all the variables

x+2

Back to the equation:

-(x+2)



We add all the numbers together, and all the variables

3x-(x+2)+14=0

We get rid of parentheses

3x-x-2+14=0

We add all the numbers together, and all the variables

2x+12=0

We move all terms containing x to the left, all other terms to the right

2x=-12

x=-12/2

x=-6

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