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3(x+4)+2x=4(x+3)+2x
We move all terms to the left:
3(x+4)+2x-(4(x+3)+2x)=0
We add all the numbers together, and all the variables
2x+3(x+4)-(4(x+3)+2x)=0
We multiply parentheses
2x+3x-(4(x+3)+2x)+12=0
We calculate terms in parentheses: -(4(x+3)+2x), so:We add all the numbers together, and all the variables
4(x+3)+2x
We add all the numbers together, and all the variables
2x+4(x+3)
We multiply parentheses
2x+4x+12
We add all the numbers together, and all the variables
6x+12
Back to the equation:
-(6x+12)
5x-(6x+12)+12=0
We get rid of parentheses
5x-6x-12+12=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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