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3(x+4)+2x=4(x-5)
We move all terms to the left:
3(x+4)+2x-(4(x-5))=0
We add all the numbers together, and all the variables
2x+3(x+4)-(4(x-5))=0
We multiply parentheses
2x+3x-(4(x-5))+12=0
We calculate terms in parentheses: -(4(x-5)), so:We add all the numbers together, and all the variables
4(x-5)
We multiply parentheses
4x-20
Back to the equation:
-(4x-20)
5x-(4x-20)+12=0
We get rid of parentheses
5x-4x+20+12=0
We add all the numbers together, and all the variables
x+32=0
We move all terms containing x to the left, all other terms to the right
x=-32
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