3(x+4)+4(5-x)=2(x-2)

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Solution for 3(x+4)+4(5-x)=2(x-2) equation: 



3(x+4)+4(5-x)=2(x-2)

We move all terms to the left:

3(x+4)+4(5-x)-(2(x-2))=0

We add all the numbers together, and all the variables

3(x+4)+4(-1x+5)-(2(x-2))=0

We multiply parentheses

3x-4x-(2(x-2))+12+20=0



We calculate terms in parentheses: -(2(x-2)), so:

2(x-2)

We multiply parentheses

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

-1x-(2x-4)+32=0

We get rid of parentheses

-1x-2x+4+32=0

We add all the numbers together, and all the variables

-3x+36=0

We move all terms containing x to the left, all other terms to the right

-3x=-36

x=-36/-3

x=+12

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