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3(x+4)+5=-2(x-5)-3
We move all terms to the left:
3(x+4)+5-(-2(x-5)-3)=0
We multiply parentheses
3x-(-2(x-5)-3)+12+5=0
We calculate terms in parentheses: -(-2(x-5)-3), so:We add all the numbers together, and all the variables
-2(x-5)-3
We multiply parentheses
-2x+10-3
We add all the numbers together, and all the variables
-2x+7
Back to the equation:
-(-2x+7)
3x-(-2x+7)+17=0
We get rid of parentheses
3x+2x-7+17=0
We add all the numbers together, and all the variables
5x+10=0
We move all terms containing x to the left, all other terms to the right
5x=-10
x=-10/5
x=-2
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