3(x+4)+7(x-2)=48

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Solution for 3(x+4)+7(x-2)=48 equation: 



3(x+4)+7(x-2)=48

We move all terms to the left:

3(x+4)+7(x-2)-(48)=0

We multiply parentheses

3x+7x+12-14-48=0

We add all the numbers together, and all the variables

10x-50=0

We move all terms containing x to the left, all other terms to the right

10x=50

x=50/10

x=5

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