3(x+4)-(4x-20)=4(x+10)

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Solution for 3(x+4)-(4x-20)=4(x+10) equation:



3(x+4)-(4x-20)=4(x+10)
We move all terms to the left:
3(x+4)-(4x-20)-(4(x+10))=0
We multiply parentheses
3x-(4x-20)-(4(x+10))+12=0
We get rid of parentheses
3x-4x-(4(x+10))+20+12=0
We calculate terms in parentheses: -(4(x+10)), so:
4(x+10)
We multiply parentheses
4x+40
Back to the equation:
-(4x+40)
We add all the numbers together, and all the variables
-1x-(4x+40)+32=0
We get rid of parentheses
-1x-4x-40+32=0
We add all the numbers together, and all the variables
-5x-8=0
We move all terms containing x to the left, all other terms to the right
-5x=8
x=8/-5
x=-1+3/5

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