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3(x+4)-12=2(x-6)+6
We move all terms to the left:
3(x+4)-12-(2(x-6)+6)=0
We multiply parentheses
3x-(2(x-6)+6)+12-12=0
We calculate terms in parentheses: -(2(x-6)+6), so:We add all the numbers together, and all the variables
2(x-6)+6
We multiply parentheses
2x-12+6
We add all the numbers together, and all the variables
2x-6
Back to the equation:
-(2x-6)
3x-(2x-6)=0
We get rid of parentheses
3x-2x+6=0
We add all the numbers together, and all the variables
x+6=0
We move all terms containing x to the left, all other terms to the right
x=-6
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