3(x+4)-2(2+2x)=3(x-6x+10+12)

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Solution for 3(x+4)-2(2+2x)=3(x-6x+10+12) equation: 



3(x+4)-2(2+2x)=3(x-6x+10+12)

We move all terms to the left:

3(x+4)-2(2+2x)-(3(x-6x+10+12))=0

We add all the numbers together, and all the variables

3(x+4)-2(2x+2)-(3(-5x+22))=0

We multiply parentheses

3x-4x-(3(-5x+22))+12-4=0



We calculate terms in parentheses: -(3(-5x+22)), so:

3(-5x+22)

We multiply parentheses

-15x+66

Back to the equation:

-(-15x+66)



We add all the numbers together, and all the variables

-1x-(-15x+66)+8=0

We get rid of parentheses

-1x+15x-66+8=0

We add all the numbers together, and all the variables

14x-58=0

We move all terms containing x to the left, all other terms to the right

14x=58

x=58/14

x=4+1/7

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