3(x+4)-2(2+2x)=3(x-6x+12+2)

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Solution for 3(x+4)-2(2+2x)=3(x-6x+12+2) equation: 



3(x+4)-2(2+2x)=3(x-6x+12+2)

We move all terms to the left:

3(x+4)-2(2+2x)-(3(x-6x+12+2))=0

We add all the numbers together, and all the variables

3(x+4)-2(2x+2)-(3(-5x+14))=0

We multiply parentheses

3x-4x-(3(-5x+14))+12-4=0



We calculate terms in parentheses: -(3(-5x+14)), so:

3(-5x+14)

We multiply parentheses

-15x+42

Back to the equation:

-(-15x+42)



We add all the numbers together, and all the variables

-1x-(-15x+42)+8=0

We get rid of parentheses

-1x+15x-42+8=0

We add all the numbers together, and all the variables

14x-34=0

We move all terms containing x to the left, all other terms to the right

14x=34

x=34/14

x=2+3/7

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