3(x+4)-2(2-x)=4(2x-1)+7

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Solution for 3(x+4)-2(2-x)=4(2x-1)+7 equation: 



3(x+4)-2(2-x)=4(2x-1)+7

We move all terms to the left:

3(x+4)-2(2-x)-(4(2x-1)+7)=0

We add all the numbers together, and all the variables

3(x+4)-2(-1x+2)-(4(2x-1)+7)=0

We multiply parentheses

3x+2x-(4(2x-1)+7)+12-4=0



We calculate terms in parentheses: -(4(2x-1)+7), so:

4(2x-1)+7

We multiply parentheses

8x-4+7

We add all the numbers together, and all the variables

8x+3

Back to the equation:

-(8x+3)



We add all the numbers together, and all the variables

5x-(8x+3)+8=0

We get rid of parentheses

5x-8x-3+8=0

We add all the numbers together, and all the variables

-3x+5=0

We move all terms containing x to the left, all other terms to the right

-3x=-5

x=-5/-3

x=1+2/3

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