3(x+4)-2=4(x-3)+6

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Solution for 3(x+4)-2=4(x-3)+6 equation: 



3(x+4)-2=4(x-3)+6

We move all terms to the left:

3(x+4)-2-(4(x-3)+6)=0

We multiply parentheses

3x-(4(x-3)+6)+12-2=0



We calculate terms in parentheses: -(4(x-3)+6), so:

4(x-3)+6

We multiply parentheses

4x-12+6

We add all the numbers together, and all the variables

4x-6

Back to the equation:

-(4x-6)



We add all the numbers together, and all the variables

3x-(4x-6)+10=0

We get rid of parentheses

3x-4x+6+10=0

We add all the numbers together, and all the variables

-1x+16=0

We move all terms containing x to the left, all other terms to the right

-x=-16

x=-16/-1

x=+16

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