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3(x+4)-32=5(x-6)
We move all terms to the left:
3(x+4)-32-(5(x-6))=0
We multiply parentheses
3x-(5(x-6))+12-32=0
We calculate terms in parentheses: -(5(x-6)), so:We add all the numbers together, and all the variables
5(x-6)
We multiply parentheses
5x-30
Back to the equation:
-(5x-30)
3x-(5x-30)-20=0
We get rid of parentheses
3x-5x+30-20=0
We add all the numbers together, and all the variables
-2x+10=0
We move all terms containing x to the left, all other terms to the right
-2x=-10
x=-10/-2
x=+5
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