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3(x+4)-5(2x+1)=4(x+3)-6(2x+3)
We move all terms to the left:
3(x+4)-5(2x+1)-(4(x+3)-6(2x+3))=0
We multiply parentheses
3x-10x-(4(x+3)-6(2x+3))+12-5=0
We calculate terms in parentheses: -(4(x+3)-6(2x+3)), so:We add all the numbers together, and all the variables
4(x+3)-6(2x+3)
We multiply parentheses
4x-12x+12-18
We add all the numbers together, and all the variables
-8x-6
Back to the equation:
-(-8x-6)
-7x-(-8x-6)+7=0
We get rid of parentheses
-7x+8x+6+7=0
We add all the numbers together, and all the variables
x+13=0
We move all terms containing x to the left, all other terms to the right
x=-13
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