3(x+4)-5(x-3)=3(x+4)-5(x-3)

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Solution for 3(x+4)-5(x-3)=3(x+4)-5(x-3) equation: 



3(x+4)-5(x-3)=3(x+4)-5(x-3)

We move all terms to the left:

3(x+4)-5(x-3)-(3(x+4)-5(x-3))=0

We multiply parentheses

3x-5x-(3(x+4)-5(x-3))+12+15=0



We calculate terms in parentheses: -(3(x+4)-5(x-3)), so:

3(x+4)-5(x-3)

We multiply parentheses

3x-5x+12+15

We add all the numbers together, and all the variables

-2x+27

Back to the equation:

-(-2x+27)



We add all the numbers together, and all the variables

-2x-(-2x+27)+27=0

We get rid of parentheses

-2x+2x-27+27=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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