3(x+4)-5=2(x-3)-4

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Solution for 3(x+4)-5=2(x-3)-4 equation: 



3(x+4)-5=2(x-3)-4

We move all terms to the left:

3(x+4)-5-(2(x-3)-4)=0

We multiply parentheses

3x-(2(x-3)-4)+12-5=0



We calculate terms in parentheses: -(2(x-3)-4), so:

2(x-3)-4

We multiply parentheses

2x-6-4

We add all the numbers together, and all the variables

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

3x-(2x-10)+7=0

We get rid of parentheses

3x-2x+10+7=0

We add all the numbers together, and all the variables

x+17=0

We move all terms containing x to the left, all other terms to the right

x=-17

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