3(x+4)-7=5(x-2)+8

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Solution for 3(x+4)-7=5(x-2)+8 equation: 



3(x+4)-7=5(x-2)+8

We move all terms to the left:

3(x+4)-7-(5(x-2)+8)=0

We multiply parentheses

3x-(5(x-2)+8)+12-7=0



We calculate terms in parentheses: -(5(x-2)+8), so:

5(x-2)+8

We multiply parentheses

5x-10+8

We add all the numbers together, and all the variables

5x-2

Back to the equation:

-(5x-2)



We add all the numbers together, and all the variables

3x-(5x-2)+5=0

We get rid of parentheses

3x-5x+2+5=0

We add all the numbers together, and all the variables

-2x+7=0

We move all terms containing x to the left, all other terms to the right

-2x=-7

x=-7/-2

x=3+1/2

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