3(x+4)-8=12-(4x-2)

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Solution for 3(x+4)-8=12-(4x-2) equation: 



3(x+4)-8=12-(4x-2)

We move all terms to the left:

3(x+4)-8-(12-(4x-2))=0

We multiply parentheses

3x-(12-(4x-2))+12-8=0



We calculate terms in parentheses: -(12-(4x-2)), so:

12-(4x-2)

determiningTheFunctionDomain
-(4x-2)+12

We get rid of parentheses

-4x+2+12

We add all the numbers together, and all the variables

-4x+14

Back to the equation:

-(-4x+14)



We add all the numbers together, and all the variables

3x-(-4x+14)+4=0

We get rid of parentheses

3x+4x-14+4=0

We add all the numbers together, and all the variables

7x-10=0

We move all terms containing x to the left, all other terms to the right

7x=10

x=10/7

x=1+3/7

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