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3(x+4)-x=x+12
We move all terms to the left:
3(x+4)-x-(x+12)=0
We add all the numbers together, and all the variables
-1x+3(x+4)-(x+12)=0
We multiply parentheses
-1x+3x-(x+12)+12=0
We get rid of parentheses
-1x+3x-x-12+12=0
We add all the numbers together, and all the variables
x=0
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