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3(x+4)7x=24
We move all terms to the left:
3(x+4)7x-(24)=0
We multiply parentheses
21x^2+84x-24=0
a = 21; b = 84; c = -24;
Δ = b2-4ac
Δ = 842-4·21·(-24)
Δ = 9072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9072}=\sqrt{1296*7}=\sqrt{1296}*\sqrt{7}=36\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-36\sqrt{7}}{2*21}=\frac{-84-36\sqrt{7}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+36\sqrt{7}}{2*21}=\frac{-84+36\sqrt{7}}{42} $
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