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3(x+4)=(x-2)+(4x+6)
We move all terms to the left:
3(x+4)-((x-2)+(4x+6))=0
We multiply parentheses
3x-((x-2)+(4x+6))+12=0
We calculate terms in parentheses: -((x-2)+(4x+6)), so:We get rid of parentheses
(x-2)+(4x+6)
We get rid of parentheses
x+4x-2+6
We add all the numbers together, and all the variables
5x+4
Back to the equation:
-(5x+4)
3x-5x-4+12=0
We add all the numbers together, and all the variables
-2x+8=0
We move all terms containing x to the left, all other terms to the right
-2x=-8
x=-8/-2
x=+4
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