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3(x+4)=-2/3(9x-18)
We move all terms to the left:
3(x+4)-(-2/3(9x-18))=0
Domain of the equation: 3(9x-18))!=0We multiply parentheses
x∈R
3x-(-2/3(9x-18))+12=0
We multiply all the terms by the denominator
3x*3(9x-18))-(+12*3(9x-18))-2=0
Wy multiply elements
9x^2(9+36x(9=0
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