3(x+4)=-4(4x-1)+7x

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Solution for 3(x+4)=-4(4x-1)+7x equation:



3(x+4)=-4(4x-1)+7x
We move all terms to the left:
3(x+4)-(-4(4x-1)+7x)=0
We multiply parentheses
3x-(-4(4x-1)+7x)+12=0
We calculate terms in parentheses: -(-4(4x-1)+7x), so:
-4(4x-1)+7x
We add all the numbers together, and all the variables
7x-4(4x-1)
We multiply parentheses
7x-16x+4
We add all the numbers together, and all the variables
-9x+4
Back to the equation:
-(-9x+4)
We get rid of parentheses
3x+9x-4+12=0
We add all the numbers together, and all the variables
12x+8=0
We move all terms containing x to the left, all other terms to the right
12x=-8
x=-8/12
x=-2/3

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