3(x+4)=-6(1+x)=

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Solution for 3(x+4)=-6(1+x)= equation: 



3(x+4)=-6(1+x)=

We move all terms to the left:

3(x+4)-(-6(1+x))=0

We add all the numbers together, and all the variables

3(x+4)-(-6(x+1))=0

We multiply parentheses

3x-(-6(x+1))+12=0



We calculate terms in parentheses: -(-6(x+1)), so:

-6(x+1)

We multiply parentheses

-6x-6

Back to the equation:

-(-6x-6)



We get rid of parentheses

3x+6x+6+12=0

We add all the numbers together, and all the variables

9x+18=0

We move all terms containing x to the left, all other terms to the right

9x=-18

x=-18/9

x=-2

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