3(x+4)=-6(3x-4)+6x

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Solution for 3(x+4)=-6(3x-4)+6x equation: 



3(x+4)=-6(3x-4)+6x

We move all terms to the left:

3(x+4)-(-6(3x-4)+6x)=0

We multiply parentheses

3x-(-6(3x-4)+6x)+12=0



We calculate terms in parentheses: -(-6(3x-4)+6x), so:

-6(3x-4)+6x

We add all the numbers together, and all the variables

6x-6(3x-4)

We multiply parentheses

6x-18x+24

We add all the numbers together, and all the variables

-12x+24

Back to the equation:

-(-12x+24)



We get rid of parentheses

3x+12x-24+12=0

We add all the numbers together, and all the variables

15x-12=0

We move all terms containing x to the left, all other terms to the right

15x=12

x=12/15

x=4/5

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