3(x+4)=2(x+1)+5

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Solution for 3(x+4)=2(x+1)+5 equation: 



3(x+4)=2(x+1)+5

We move all terms to the left:

3(x+4)-(2(x+1)+5)=0

We multiply parentheses

3x-(2(x+1)+5)+12=0



We calculate terms in parentheses: -(2(x+1)+5), so:

2(x+1)+5

We multiply parentheses

2x+2+5

We add all the numbers together, and all the variables

2x+7

Back to the equation:

-(2x+7)



We get rid of parentheses

3x-2x-7+12=0

We add all the numbers together, and all the variables

x+5=0

We move all terms containing x to the left, all other terms to the right

x=-5

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