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3(x+4)=2(x+6)+x
We move all terms to the left:
3(x+4)-(2(x+6)+x)=0
We multiply parentheses
3x-(2(x+6)+x)+12=0
We calculate terms in parentheses: -(2(x+6)+x), so:We get rid of parentheses
2(x+6)+x
We add all the numbers together, and all the variables
x+2(x+6)
We multiply parentheses
x+2x+12
We add all the numbers together, and all the variables
3x+12
Back to the equation:
-(3x+12)
3x-3x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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