3(x+4)=2(x-7)+x+20

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Solution for 3(x+4)=2(x-7)+x+20 equation: 



3(x+4)=2(x-7)+x+20

We move all terms to the left:

3(x+4)-(2(x-7)+x+20)=0

We multiply parentheses

3x-(2(x-7)+x+20)+12=0



We calculate terms in parentheses: -(2(x-7)+x+20), so:

2(x-7)+x+20

We add all the numbers together, and all the variables

x+2(x-7)+20

We multiply parentheses

x+2x-14+20

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

3x-3x-6+12=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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