3(x+4)=3(x+3)+x

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Solution for 3(x+4)=3(x+3)+x equation: 



3(x+4)=3(x+3)+x

We move all terms to the left:

3(x+4)-(3(x+3)+x)=0

We multiply parentheses

3x-(3(x+3)+x)+12=0



We calculate terms in parentheses: -(3(x+3)+x), so:

3(x+3)+x

We add all the numbers together, and all the variables

x+3(x+3)

We multiply parentheses

x+3x+9

We add all the numbers together, and all the variables

4x+9

Back to the equation:

-(4x+9)



We get rid of parentheses

3x-4x-9+12=0

We add all the numbers together, and all the variables

-1x+3=0

We move all terms containing x to the left, all other terms to the right

-x=-3

x=-3/-1

x=+3

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