3(x+4)=3x+113(x+4)=3x+11

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Solution for 3(x+4)=3x+113(x+4)=3x+11 equation: 



3(x+4)=3x+113(x+4)=3x+11

We move all terms to the left:

3(x+4)-(3x+113(x+4))=0

We multiply parentheses

3x-(3x+113(x+4))+12=0



We calculate terms in parentheses: -(3x+113(x+4)), so:

3x+113(x+4)

We multiply parentheses

3x+113x+452

We add all the numbers together, and all the variables

116x+452

Back to the equation:

-(116x+452)



We get rid of parentheses

3x-116x-452+12=0

We add all the numbers together, and all the variables

-113x-440=0

We move all terms containing x to the left, all other terms to the right

-113x=440

x=440/-113

x=-3+101/113

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