3(x+4)=3x2+4

Solution for 3(x+4)=3x2+4 equation:

3(x+4)=3x^2+4

We move all terms to the left:

3(x+4)-(3x^2+4)=0

We multiply parentheses

3x-(3x^2+4)+12=0

We get rid of parentheses

-3x^2+3x-4+12=0

We add all the numbers together, and all the variables

-3x^2+3x+8=0

a = -3; b = 3; c = +8;
Δ = b2-4ac
Δ = 32-4·(-3)·8
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{105}}{2*-3}=\frac{-3-\sqrt{105}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{105}}{2*-3}=\frac{-3+\sqrt{105}}{-6}
$