3(x+4)=4(-8+x)

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Solution for 3(x+4)=4(-8+x) equation: 



3(x+4)=4(-8+x)

We move all terms to the left:

3(x+4)-(4(-8+x))=0

We add all the numbers together, and all the variables

3(x+4)-(4(x-8))=0

We multiply parentheses

3x-(4(x-8))+12=0



We calculate terms in parentheses: -(4(x-8)), so:

4(x-8)

We multiply parentheses

4x-32

Back to the equation:

-(4x-32)



We get rid of parentheses

3x-4x+32+12=0

We add all the numbers together, and all the variables

-1x+44=0

We move all terms containing x to the left, all other terms to the right

-x=-44

x=-44/-1

x=+44

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