3(x+4)=4(x-1)+14

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Solution for 3(x+4)=4(x-1)+14 equation: 



3(x+4)=4(x-1)+14

We move all terms to the left:

3(x+4)-(4(x-1)+14)=0

We multiply parentheses

3x-(4(x-1)+14)+12=0



We calculate terms in parentheses: -(4(x-1)+14), so:

4(x-1)+14

We multiply parentheses

4x-4+14

We add all the numbers together, and all the variables

4x+10

Back to the equation:

-(4x+10)



We get rid of parentheses

3x-4x-10+12=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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