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3(x+4)=4x-x+12
We move all terms to the left:
3(x+4)-(4x-x+12)=0
We add all the numbers together, and all the variables
3(x+4)-(3x+12)=0
We multiply parentheses
3x-(3x+12)+12=0
We get rid of parentheses
3x-3x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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