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3(x+4)=5(x+2)+2
We move all terms to the left:
3(x+4)-(5(x+2)+2)=0
We multiply parentheses
3x-(5(x+2)+2)+12=0
We calculate terms in parentheses: -(5(x+2)+2), so:We get rid of parentheses
5(x+2)+2
We multiply parentheses
5x+10+2
We add all the numbers together, and all the variables
5x+12
Back to the equation:
-(5x+12)
3x-5x-12+12=0
We add all the numbers together, and all the variables
-2x=0
x=0/-2
x=0
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